连接
目录
A:开开心心233
B:Square Game
C:室温超导
F:necklace
K:tourist
补题中，会给出大部分代码
A:开开心心233
签到题 ，无论二分还是解方程还是直接for循环枚举都能直接通过啦
signed main()
{ios_base::sync_with_stdio(0); cin.tie(0),cout.tie(0);int n,m;cin>>n>>m;
// cout<<-3+sqrt(3*3+4*2*(n+m))<<'\n';int res1=n-(-3+sqrt(3*3+4*2*(n+m)))/2;int res2=n-(-3-sqrt(3*3+4*2*(n+m)))/2;if(res1<=n&&res1>=0) cout<<res1;else cout<<res2;
}B:Square Game
#define f first
#define s second
const int N=1e6+5;
int f[N];
void init()
{for(int i=1;i<N;i++){int q=sqrt(i);map<int,bool>mp;if(q*q==i||q*q+1==i){for(int j=0;j<i;j+=q){mp[f[j]]=1;}int cnt=0;for(auto w:mp){if(w.f==cnt) cnt++;else break;}f[i]=cnt;}else{f[i]=f[i-1];}}
}
signed main() {ios_base::sync_with_stdio(0);cin.tie(0),cout.tie(0);init();int n;cin>>n;int sum=0;for(int i=1;i<=n;i++){int x;cin>>x;sum^=f[x];}if(sum==0){cout<<"Second\n";}else{cout<<"First\n";}
}C:室温超导
#define int long long
#define f first
#define s second
const int N = 500000 + 5;
char str[N];
struct Node
{int len, fa;int ch[26];
}node[N*4];
int tot = 1, last = 1;
int summ = 0;//不同的子串数
void extend(int c)
{int p = last, np = last = ++tot;node[np].len = node[p].len + 1;for (; p && !node[p].ch[c]; p = node[p].fa) node[p].ch[c] = np;if (!p) {node[np].fa = 1; summ += node[np].len - node[node[np].fa].len;}else{int q = node[p].ch[c];if (node[q].len == node[p].len + 1) { node[np].fa = q; summ += node[np].len - node[node[np].fa].len; }else {int nq = ++tot;summ -= node[q].len - node[node[q].fa].len;node[nq] = node[q], node[nq].len = node[p].len + 1;node[q].fa = node[np].fa = nq;summ += node[q].len - node[node[q].fa].len;summ += node[np].len - node[node[np].fa].len;summ += node[nq].len - node[node[nq].fa].len;for (; p && node[p].ch[c] == q; p = node[p].fa) node[p].ch[c] = nq;}}
}
signed main() {ios_base::sync_with_stdio(0);cin.tie(0), cout.tie(0);int n, m;cin >> n >> m;cin >> str + 1;string t;cin >> t;t = ' ' + t;vector<int>sum(30);int all = 0;//int summ = 0;;for (int i = 1; i <= n - m + 1; i++) {int pre_tot = summ;extend(str[i] - 'a');// summ = 0;// for (int j = 2; j <= tot; j++) {// summ += node[j].len - node[node[j].fa].len;// }sum[str[i] - 'a'] += (summ - pre_tot);}all += summ;for (int i = n - m + 2; str[i]; i++) {int j = i - (n - m);int pre_tot = summ;extend(str[i] - 'a');// summ = 0;// for (int j = 2; j <= tot; j++) {// summ += node[j].len - node[node[j].fa].len;// }sum[str[i] - 'a'] += (summ - pre_tot);all += summ;all -= sum[t[j - 1] - 'a'];if (sum[t[j - 1] - 'a']) all++;}cout << all;
}F:necklace
const int inf=0x3f3f3f3f;
int change[410][410];signed main()
{ios_base::sync_with_stdio(0); cin.tie(0),cout.tie(0);memset(change,0x3f,sizeof change);int n,m;cin>>n>>m;vector<int>s(n),t(n);for(int i=0;i<n;i++){cin>>s[i];}for(int i=0;i<n;i++){cin>>t[i];}while(m--){int a,b,c;cin>>a>>b>>c;change[a][b]=min(change[a][b],c);}for(int k=1;k<=400;k++){for(int i=1;i<=400;i++){for(int j=1;j<=400;j++){change[i][j]=min(change[i][j],change[i][k]+change[k][j]);}}}bool ok=0;int tot=inf;for(int i=0;i<n;i++){int sum=0;bool flag=1;for(int j=0;j<n;j++){if(s[j]==t[(i+j)%n]) continue;int p=inf;p=min(change[s[j]][t[(i+j)%n]],p);p=min(change[t[(i+j)%n]][s[j]],p);if(p>=inf){flag=0;break; }sum+=p;}if(flag==0){
// ok=0;
// break;}else{ok=1;tot=min(tot,sum);}}if(!ok){cout<<-1<<'\n';}else{cout<<tot<<'\n';}
}K:tourist
#define int long long
const int K=1<<7,mod=1e9+9;
int path[21][21];
int st[K];
int sz[10];
int siz(int x) {int cnt=0;while(x) {if(x&1) cnt++;x>>=1;}return cnt;
}
int a[21][21];
int f[21];
int n,m,k,d;
void mul(int f[],int a[21][21]) {int c[21]= {0};for(int j=1; j<=n; j++) {for(int k=1; k<=n; k++) {c[j]=(c[j]+f[k]*a[k][j])%mod;}}memcpy(f,c,sizeof c);
}
void mulself(int a[21][21]) {int c[21][21]= {0};for(int i=1; i<=n; i++) {for(int j=1; j<=n; j++) {for(int k=1; k<=n; k++) {c[i][j]=(c[i][j]+a[i][k]*a[k][j])%mod;}}}memcpy(a,c,sizeof c);
}
signed main() {ios_base::sync_with_stdio(0);cin.tie(0),cout.tie(0);cin>>n>>m>>k>>d;d--;for(int i=0; i<k; i++) {int x;cin>>x;st[(1ll<<i)]=x;}while(m--) {int u,v;cin>>u>>v;path[u][v]=1;path[v][u]=1;}for(int i=0; i<(1ll<<k); i++) {int size=siz(i);memcpy(a,path,sizeof path);for(int j=0; j<k; j++) {if((i>>j)&1) {int p=st[(1ll<<j)];for(int k=1; k<=n; k++) {a[p][k]=0;a[k][p]=0;}}}for(int ii=1; ii<=n; ii++) {f[ii]=1;}int dd=d;for(; dd; dd>>=1) {if(dd&1) mul(f,a);mulself(a);}for(int j=1; j<=n; j++) {sz[size]+=f[j];sz[size]%=mod;}}int sum=0;for(int i=0; i<=k; i++) {if(i%2==0) {sum+=sz[i];sum%=mod;} else {sum=(sum-sz[i]+mod)%mod;}}cout<<sum<<'\n';
}
