试编写算法将带头结点的单链表就地逆置，所谓“就地”是指空间复杂度为 O(1)。

#include <iostream>
using namespace std;typedef int Elemtype;
#define ERROR 0;
#define OK    1;typedef struct LNode
{Elemtype data;      //结点保存的数据struct LNode* next; //结构体指针
}LNode, * LinkList;/*单链表初始化*/
bool Init_LinkList(LinkList& L)
{L = (LinkList)malloc(sizeof(LNode));  //新建头结点if (L == NULL){return ERROR;}L->data = 0;L->next = NULL;return OK;
}
/*单链表头插法*/
bool LinkList_head_instert(LinkList& L)
{int x = 0;LNode* p = NULL;while (cin >> x){p = (LinkList)malloc(sizeof(LNode));if (p != NULL)  //防止分配地址失败{p->data = x;p->next = L->next;L->next = p;if (cin.get() == '\n') break;  //检测换行符}else{exit(0);cout << "内存分配失败" << endl;}}return OK;
}
/*单链表尾插法*/
bool LinkList_tail_instert(LinkList& L)
{int x = 0;LNode* p = NULL;LNode* r = NULL;r = L;while (cin >> x){p = (LinkList)malloc(sizeof(LNode));if (p != NULL)  //防止分配地址失败{p->data = x;p->next = NULL;r->next = p;r = p;if (cin.get() == '\n') break;  //检测换行符}else{exit(0);cout << "内存分配失败" << endl;}}return OK;
}/*单链表遍历*/
bool LinkList_All_value(LinkList L)
{if (L->next == NULL){cout << "链表为空" << endl;return ERROR;}LNode* s = NULL;s = L->next;while (s != NULL){cout << s->data << "   ";s = s->next;}cout << endl;free(s);return OK;
}/*单链表长度*/
int LinkList_length(LinkList L)
{int count = 0;LNode* s = NULL;s = L->next;while (s != NULL){count++;s = s->next;}return count;
}/*清空单链表*/
void Clear_LinkList(LinkList& L)
{LNode* p = L->next;LNode* q = NULL;while (p != NULL){q = p->next;free(p);p = q;}L->next = NULL;
}/*销毁单链表*/
void Destory_LinkList(LinkList& L)
{LNode* p = NULL;LNode* q = NULL;p = L;while (p != NULL){q = p->next;free(p);p = q;}L = NULL;
}//-----------------------------------------核心代码-----------------------------------------//
bool reverse(LinkList &L)
{LNode* p = NULL;LNode* r = NULL;p = L->next;if (L->next == NULL){cout << "单链表数据为空!!!" << endl;return ERROR;}L->next = NULL;while (p!=NULL){r = p->next;p->next = L->next;L->next = p;p = r;}return OK;
}
//-----------------------------------------核心代码-----------------------------------------////试编写算法将带头结点的单链表就地逆置，所谓“就地”是指空间复杂度为 O(1)。
int main(void)
{LinkList L1 = NULL;Init_LinkList(L1);LinkList_tail_instert(L1);//1 2 3 4reverse(L1);LinkList_All_value(L1);return 0;
}