2.3_8 多生产者-多消费者问题

实现思路

semaphore mutex=1;	//实现互斥访问盘子(缓冲区)
semaphore apple=0;	//盘子中有几个苹果
semaphore orange=0;	//盘子中有几个橘子
semaphore plate =1;	//盘子中还可以放多少个水果dad(){while(1){准备一个苹果;P(plate);P(mutex);把苹果放入盘子;V(mutex);V(apple);}
}mom(){while(1){准备一个橘子;P(plate);P(mutex);把橘子放入盘子;V(mutex);V(orange);}
}daughter(){while(1){P(apple);P(mutex);从盘中取出苹果;V(mutex);V(apple);吃掉苹果;}
}son(){while(1){P(orange);P(mutex);从盘中取出橘子;V(mutex);V(orange);吃掉苹橘子;}
}

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知识回顾与重要考点