- 在Complex类的基础上，完成^，>，~运算符的重载
#include <iostream>using namespace std; class Complex {int rel; //实部int vir; //虚部 public:Complex(){}Complex(int rel,int vir):rel(rel),vir(vir){}/* Complex operator+(const Complex c1);Complex operator-(const Complex c1);Complex operator*(const Complex c1);Complex operator/(const Complex c1);*/friend Complex operator+(const Complex c1,const Complex c2);friend Complex operator-(const Complex c1,const Complex c2);friend Complex operator*(const Complex c1,const Complex c2);friend Complex operator/(const Complex c1,const Complex c2);bool operator>(const Complex c1);bool operator<(const Complex c1);bool operator>=(const Complex c1);bool operator<=(const Complex c1);bool operator==(const Complex c1);bool operator!=(const Complex c1);bool operator!();bool operator&&(const Complex c1);bool operator||(const Complex c1);Complex operator++();Complex operator--();friend Complex operator++(Complex &c1,int );friend Complex operator--(Complex &c1,int );friend ostream &operator<<(ostream &out,Complex c1);friend istream &operator>>(istream &in,Complex &c1);Complex operator^(Complex c1);Complex operator<<(int a);Complex operator>>(int a);Complex operator~();Complex show(){cout << rel << "+"<< vir << "i" << endl;}operator int(){return this->rel;}operator double(){return this->rel;}operator char(){return 'a';}int operator()(int a,int b ){return a>b?a:b;} }; //^,<<,>>,~ Complex Complex::operator^(Complex c1) {Complex temp;temp.rel=(this->rel)^c1.rel;temp.vir=(this->vir)^c1.vir;return temp; } Complex Complex::operator<<(int a) {rel=rel<<a;vir=vir<<a;return *this; } Complex Complex::operator>>(int a) {rel=rel>>a;vir=vir>>a;return *this; } Complex Complex::operator~() {rel=~rel;vir=~vir;return *this; } //自增自减 Complex Complex::operator++() {++this->rel;++this->vir;return *this; } Complex Complex::operator--() {--this->rel;--this->vir;return *this; } Complex operator++(Complex &c1,int ) {Complex temp=c1;c1.rel++;c1.vir++;return temp; } Complex operator--(Complex &c1,int ) {Complex temp=c1;c1.rel--;c1.vir--;return temp; }//关系 bool Complex::operator!() {return !(this->rel || this->vir); } bool Complex::operator&&(const Complex c1) {return this->rel && c1.rel && this->vir && c1.vir; } bool Complex::operator||(const Complex c1) {return this->rel || c1.rel || this->vir || c1.vir; } bool Complex::operator>(const Complex c1) {return this->rel>c1.rel; } bool Complex::operator<(const Complex c1) {return this->rel<c1.rel; } bool Complex::operator>=(const Complex c1) {return this->rel>=c1.rel; } bool Complex::operator<=(const Complex c1) {return this->rel<=c1.rel; } bool Complex::operator==(const Complex c1) {return this->rel==c1.rel&&this->vir==c1.vir; } bool Complex::operator!=(const Complex c1) {return this->rel!=c1.rel||this->vir!=c1.vir; }//加减乘除 Complex operator+(const Complex c1,const Complex c2) {Complex temp;temp.rel = c1.rel + c2.rel;temp.vir = c1.vir + c2.vir;return temp; } Complex operator-(const Complex c1,const Complex c2) {Complex temp;temp.rel = c1.rel - c2.rel;temp.vir = c1.vir - c2.vir;return temp; } Complex operator*(const Complex c1,const Complex c2) {Complex temp;temp.rel = c1.rel * c2.rel-c1.vir * c2.vir;temp.vir = c1.vir * c2.rel+c1.rel * c2.vir;return temp; } Complex operator/(const Complex c1,const Complex c2) {Complex temp;int a = c1.rel;int b = c1.vir;int c = c2.rel;int d = c2.vir;temp.rel = (a*c+b*d)/(c*c-d*d);temp.vir = (b*c-a*d)/(c*c+d*d);return temp; } /* Complex Complex::operator+(const Complex c1) {Complex temp;temp.rel = this ->rel+c1.rel;temp.vir = this->vir +c1.vir;return temp; } Complex Complex::operator-(const Complex c1) {Complex temp;temp.rel = this->rel - c1.rel;temp.vir = this->vir - c1.vir;return temp; }Complex Complex::operator*(const Complex c1) {Complex temp;temp.rel = this->rel * c1.rel;temp.vir = this->vir * c1.vir;return temp; }Complex Complex::operator/(const Complex c1) {Complex temp;temp.rel = this->rel / c1.rel;temp.vir = this->vir / c1.vir;return temp; }*///输出 ostream &operator<<(ostream &out,Complex c1) {out << c1.rel << "+" << c1.vir << "i" ;return out; } //输出 istream &operator>>(istream &in,Complex &c1) {in >> c1.rel >> c1.vir;return in; }int main() {Complex c1(4,6),c2(4,0),c3(1,2),c4;// cin >> c3 >> c4 ;// cout << c3 << endl << c4 << endl;cout << (c1<<1) << endl << (c2>>1) << endl;cout << ~c3 <<endl;c4 = c1^c2 ;cout << c4 <<endl;return 0; }
myString类的基础上，完成+、关系运算符、逻辑运算符、输入输出运算符的重载
#include <iostream>
#include <cstring>
using namespace std;
char c = '\0';
class myString
{private:char *str; //记录c风格的字符串int size; //记录字符串的实际长度public://无参构造myString():str(new char[20]),size(0){}//有参构造myString(char *p,int size):str(new char[size+1]),size(size){strcpy(str,p);}myString(string s1):str(new char[s1.size()+1]),size(s1.length()){strcpy(str,s1.c_str());}//拷贝构造myString(const myString &other):str(new char[other.size+1]),size(size){strcpy(str,other.str);}//拷贝赋值函数myString &operator=(const myString &other){//提前把申请的空间释放，重新申请空间，为了防止原有的空间不够存下新的内容if(&other!=this){delete []str;str = new char[other.size+1];strcpy(str,other.str);this->size = other.size;}return *this;}//析构函数~myString(){delete []str;}//判空函数bool empty(){return size==0;}//size函数int size_(){return size;}//c_str函数const char *c_str(){return str;}//at函数char &at(int pos){//判断位置合理性if(pos<0||pos>=size){cout << "位置不合理" << endl;return c;}return str[pos];}myString operator+(const myString s1);bool operator>(const myString s1);bool operator&&(const myString s1);bool operator||(const myString s1);friend ostream &operator<<(ostream &out,myString s1);friend istream &operator>>(istream &in,myString &s1);
};
ostream &operator<<(ostream &out,myString s1)
{out << s1.str;return out;
}
istream &operator>>(istream &in,myString &s1)
{in >> s1.str;return in;
}
myString myString::operator+( myString s1)
{strcat(this->str,s1.str);return *this;
}
bool myString::operator>( myString s1)
{return strcmp(this->str,s1.str);
}
bool myString::operator&&( myString s1)
{return this->str&&s1.str;
}
bool myString::operator||( myString s1)
{return this->str||s1.str;
}
int main()
{myString s1,s2;cin >> s1 >> s2;cout <<"s1 = "<< s1 << endl << "s2 = " << s2 << endl;cout << "s1+s2 = " << s1+s2 << endl;cout << "s1>s2 = " << (s1>s2) <<endl;cout << "s1&&s2 = " << (s1&&s2) <<endl;return 0;
} 
