题目
请你判断一个 9 x 9
的数独是否有效。只需要 根据以下规则 ,验证已经填入的数字是否有效即可。
- 数字
1-9
在每一行只能出现一次。 - 数字
1-9
在每一列只能出现一次。 - 数字
1-9
在每一个以粗实线分隔的3x3
宫内只能出现一次。(请参考示例图)
注意:
- 一个有效的数独(部分已被填充)不一定是可解的。
- 只需要根据以上规则,验证已经填入的数字是否有效即可。
- 空白格用
'.'
表示。
示例 1:
输入:board = [["5","3",".",".","7",".",".",".","."] ,["6",".",".","1","9","5",".",".","."] ,[".","9","8",".",".",".",".","6","."] ,["8",".",".",".","6",".",".",".","3"] ,["4",".",".","8",".","3",".",".","1"] ,["7",".",".",".","2",".",".",".","6"] ,[".","6",".",".",".",".","2","8","."] ,[".",".",".","4","1","9",".",".","5"] ,[".",".",".",".","8",".",".","7","9"]] 输出:true
示例 2:
输入:board = [["8","3",".",".","7",".",".",".","."] ,["6",".",".","1","9","5",".",".","."] ,[".","9","8",".",".",".",".","6","."] ,["8",".",".",".","6",".",".",".","3"] ,["4",".",".","8",".","3",".",".","1"] ,["7",".",".",".","2",".",".",".","6"] ,[".","6",".",".",".",".","2","8","."] ,[".",".",".","4","1","9",".",".","5"] ,[".",".",".",".","8",".",".","7","9"]] 输出:false 解释:除了第一行的第一个数字从 5 改为 8 以外,空格内其他数字均与 示例1 相同。 但由于位于左上角的 3x3 宫内有两个 8 存在, 因此这个数独是无效的。
提示:
board.length == 9
board[i].length == 9
board[i][j]
是一位数字(1-9
)或者'.'
代码
#include <stdio.h>
#include <string.h>
#include <stdbool.h>bool isValidSudoku(char **board, int boardSize, int *boardColSize);int main()
{char *board[] ={"....5..1.", ".4.3.....", ".....3..1", "8......2.", "..2.7....", ".....2...", ".6....28.", ".2.9.....", "..4......"};int t, *te; printf("%d", isValidSudoku(board, t, te));return 0;
}bool isValidSudoku(char **board, int boardSize, int *boardColSize)//后两个参数没有用
{int rownums[10], colnums[10];memset(rownums, 0, sizeof(rownums));memset(colnums, 0, sizeof(colnums));for (int i = 0; i < 9; i++){for (int j = 0; j < 9; j++){if (board[i][j] != '.'){int number = board[i][j] - '0';if (rownums[number] == 0){rownums[number] = 1;}elsereturn false;}if (board[j][i] != '.'){int number = board[j][i] - '0';if (colnums[number] == 0){colnums[number] = 1;}elsereturn false;}}memset(rownums, 0, sizeof(rownums));memset(colnums, 0, sizeof(colnums));}int i = 0, j = 0;for (int p = 3; p <= 9; p = p + 3){for (int q = 3; q <= 9; q = q + 3){i=p-3;for (; i < p; i++){j=q-3;for (; j < q; j++){if (board[i][j] != '.'){int number = board[i][j] - '0';if (rownums[number] == 0){rownums[number] = 1;}elsereturn false;}}}memset(rownums, 0, sizeof(rownums)); }}return true;
}