使用boost::geometry::union_ 合并边界（内、外）：方案二-编程知识

使用boost::geometry::union_ 合并边界（内、外）：方案二


typedef boost::geometry::model::d2::point_xy<double> boost_point;
typedef boost::geometry::model::polygon<boost_point> boost_Polygon;struct Point
{float x;float y;Point(float _x,float _y){x = _x;y = _y;}Point(const boost_point & pt){x = pt.x();y = pt.y();}operator boost_point(){return boost_point(x, y);}
};bool TestClientTrafficEvent::TestBorderCombine()
{//str_points_of_cur_frame_data = "POLYGON((1.500000 1.500000,1.500000 2.500000,2.500000 2.500000,2.500000 1.500000,1.500000 1.500000))".std::vector<Point> lhs;{Point lhs_p1(1.5, 1.5); Point lhs_p2(1.5,2.5); //remainPoint lhs_p3(2.5, 2.5); //remainPoint lhs_p4(2.5, 1.5);Point lhs_p5(1.5, 1.5);lhs.push_back(lhs_p1);lhs.push_back(lhs_p2);lhs.push_back(lhs_p3);lhs.push_back(lhs_p4);lhs.push_back(lhs_p5);}//str_points_of_compared_frame_data = "POLYGON((1.000000 1.000000,1.000000 2.000000,2.000000 2.000000,2.000000 1.000000,1.000000 1.000000))";std::vector<Point> rhs;{Point rhs_p1(1.0, 1.0); Point rhs_p2(1.0, 2.0);Point rhs_p3(2.0, 2.0);Point rhs_p4(2.0, 1.0);Point rhs_p5(1.0, 1.0);    }boost_Polygon lhs_lt, rhs_lt;for (auto & pt : lhs){boost::geometry::append(lhs_lt, (boost_point)pt);}for (auto & pt : rhs){boost::geometry::append(rhs_lt, (boost_point)pt);}//进行并集计算std::vector<boost_Polygon> r;boost::geometry::union_(lhs_lt, rhs_lt, r);//通过验证：与传入的顺序无关，均返回相同的结果。std::vector<Point> vctr_combined ;if (!r.empty())//有结果返回{for (auto & pt : r[0].outer()){vctr_combined.push_back(pt);}}    std::cout << "vctr_combined.size()  = " << vctr_combined.size() << std::endl;for(auto iter : vctr_combined){std::cout << "iter.x  = " << iter.x << ", iter.y  = " << iter.y << std::endl;}return true;}