Oracle 经典练习题 50 题

文章目录

  • 一 CreateTable
  • 二 练习题
    • 1 查询"01"课程比"02"课程成绩高的学生的信息及课程分数
    • 2 查询"01"课程比"02"课程成绩低的学生的信息及课程分数
    • 3 查询平均成绩大于等于60分的同学的学生编号和学生姓名和平均成绩
    • 4 查询平均成绩小于60分的同学的学生编号和学生姓名和平均成绩(包括有成绩的和无成绩的)
    • 5 查询所有同学的学生编号、学生姓名、选课总数、所有课程的总成绩
    • 6 查询"李"姓老师的数量
    • 7 查询学过"张三"老师授课的同学的信息
    • 8 查询没学过"张三"老师授课的同学的信息
    • 9 查询学过编号为"01"并且也学过编号为"02"的课程的同学的信息
    • 10 查询学过编号为"01"但是没有学过编号为"02"的课程的同学的信息
    • 11 查询没有学全所有课程的同学的信息
    • 12 查询至少有一门课与学号为"01"的同学所学相同的同学的信息
    • 13 查询和"01"号的同学学习的课程完全相同的其他同学的信息
    • 14 查询没学过"张三"老师讲授的任一门课程的学生姓名
    • 15 查询两门及其以上不及格课程的同学的学号,姓名及其平均成绩
    • 16 检索"01"课程分数小于60,按分数降序排列的学生信息
    • 17 按平均成绩从高到低显示所有学生的所有课程的成绩以及平均成绩
    • 18 查询各科成绩最高分、最低分和平均分,以如下形式显示
    • 19 按各科成绩进行排序,并显示排名
    • 20 查询学生的总成绩并进行排名
    • 21 查询不同老师所教不同课程平均分从高到低显示
    • 22 查询所有课程的成绩第2名到第3名的学生信息及该课程成绩
    • 23 统计各科成绩各分数段人数:课程编号,课程名称,[100-85),[85-70),[70-60),[0-60)及所占百分比
    • 24 查询学生平均成绩及其名次
    • 25 查询各科成绩前三名的记录
    • 26 查询每门课程被选修的学生数
    • 27 查询出只有两门课程的全部学生的学号和姓名
    • 28 查询男生、女生人数
    • 29 查询名字中含有"风"字的学生信息
    • 30 统计同姓的人员名单,打印 姓 人数 姓名
    • 31 查询1990年出生的学生名单
    • 32 查询每门课程的平均成绩,结果按平均成绩降序排列,平均成绩相同时,按课程编号升序排列
    • 33 查询平均成绩大于等于85的所有学生的学号、姓名和平均成绩
    • 34 查询课程名称为"数学",且分数低于60的学生姓名和分数
    • 35 查询所有学生的课程及分数情况
          • Result1 group
          • Result2 pivot
    • 36 查询任何一门课程成绩在70分以上的学生姓名、课程名称和分数
    • 37 查询课程不及格的学生
    • 38 查询课程编号为01且课程成绩在80分以上的学生的学号和姓名
    • 39 查询每门课程的人数
    • 40 查询选修"张三"老师所授课程的学生中,成绩最高的学生信息及其成绩
    • 41 查询不同课程成绩相同的学生的学生编号、课程编号、学生成绩
    • 42 统计每门课程的前几名
    • 43 统计课程的选课人数,> 5 才统计
    • 44 查询选修了2门课的sid
    • 45 查询选修了全部课程的学生信息
    • 46 求学生周岁
    • 47 本周过生日的同学
    • 48 下周过生日的同学
    • 49 查询本月过生日的同学
    • 50 查询12月份过生日的同学

先用sys创建一个用户,防止其他表带来干扰

CREATE USER c##baseMyf IDENTIFIED BY 123456GRANT CONNECT, RESOURCE, DBA TO c##baseMyf;alter user c##ifeng identified by 123456;

一 CreateTable

image.png

--Studentcreate table student (s_id int,s_name varchar(8),s_birth date,s_sex varchar(4)
);
go
insert into student values
(1,'赵雷',to_date('1990-01-01','yyyy-MM-dd'),'男');insert into student values
(2,'钱电',to_date('1990-12-21','yyyy-MM-dd'),'男');insert into student values
(3,'孙风',to_date('1990-05-20','yyyy-MM-dd'),'男');insert into student values
(4,'李云',to_date('1990-08-06','yyyy-MM-dd'),'男');insert into student values
(5,'周梅',to_date('1991-12-01','yyyy-MM-dd'),'女');insert into student values
(6,'吴兰',to_date('1992-03-01','yyyy-MM-dd'),'女');insert into student values
(7,'郑竹',to_date('1989-07-01','yyyy-MM-dd'),'女');insert into student values
(8,'王菊',to_date('1990-01-20','yyyy-MM-dd'),'女');--course
create table course (c_id int,c_name varchar(8),t_id int
);insert into course values
(1,'语文',2);
insert into course values
(2,'数学',1);
insert into course values
(3,'英语',3);-- teachercreate table teacher (t_id int,t_name varchar(8)
);insert into teacher values
(1,'张三');
insert into teacher values
(2,'李四');
insert into teacher values
(3,'王五');--score
create table score (s_id int,c_id int,s_score int
);insert into score values
(1,1,80);
insert into score values
(1,2,90);
insert into score values
(1,3,99);
insert into score values
(2,1,70);
insert into score values
(2,2,60);
insert into score values
(2,3,65);
insert into score values
(3,1,80);
insert into score values
(3,2,80);
insert into score values
(3,3,80);
insert into score values
(4,1,50);
insert into score values
(4,2,30);
insert into score values
(4,3,40);
insert into score values
(5,1,76);
insert into score values
(5,2,87);
insert into score values
(6,1,31);
insert into score values
(6,3,34);
insert into score values
(7,2,89);
insert into score values
(7,3,98);

二 练习题

1 查询"01"课程比"02"课程成绩高的学生的信息及课程分数

--查询"01"课程比"02"课程成绩高的学生的信息及课程分数
select distinct stu.s_id, s_name, s_birth, s_sex ,s_score_1,s_score_2
from student stu
join score s on s.s_id = stu.s_id
join (select s_id ,max(case when c_id = 1 then s_score end) as s_score_1,max(case when c_id = 2 then s_score end) as s_score_2from scoregroup by s_idhaving max(case when c_id = 1 then s_score end) > max(case when c_id = 2 then s_score end)
)a on stu.s_id = a.s_id

image.png

2 查询"01"课程比"02"课程成绩低的学生的信息及课程分数

--查询"01"课程比"02"课程成绩低的学生的信息及课程分数(查询了全部的课程分数)select distinct stu.s_id, s_name, s_birth, s.c_id,s.s_score
from student stu
join score s on stu.s_id = s.s_id
and s.s_id in  (select s_id--,max(case when c_id = 1 then s_score end) as score_1--,max(case when c_id = 2 then s_score end) as score_2from scoregroup by s_idhaving max(case when c_id = 1 then s_score end) < max(case when c_id = 2 then s_score end) 
)

3 查询平均成绩大于等于60分的同学的学生编号和学生姓名和平均成绩

--查询平均成绩大于等于60分的同学的学生编号和学生姓名和平均成绩select stu.s_id, s_name, s_birth, s_sex ,a.avg_score
from student stu
join (
select s_id,round(avg(s_score),2) as avg_score
from score
group by s_id
having avg(s_score) > 60) a on a.s_id = stu.s_id

4 查询平均成绩小于60分的同学的学生编号和学生姓名和平均成绩(包括有成绩的和无成绩的)

--查询平均成绩小于60分的同学的学生编号和学生姓名和平均成绩(包括有成绩的和无成绩的)
select stu.s_id, s_name, s_birth, s_sex ,a.avg_score,a.avg_score_2
from student stu
left join (select s_id--, c_id, s_score ,round(sum(s_score) / count(coalesce(c_id,1)),2) as avg_score,avg(s_score) as avg_score_2from scoregroup by s_id
) a on a.s_id = stu.s_id
where (avg_score < 60 or avg_score is null)

image.png

5 查询所有同学的学生编号、学生姓名、选课总数、所有课程的总成绩

--查询所有同学的学生编号、学生姓名、选课总数、所有课程的总成绩select stu.s_id, s_name,coalesce(count_c,0),coalesce(sum_score,0)
from student stu
left join (select s_id--, c_id, s_score ,count(c_id) as count_c,sum(s_score) as sum_scorefrom scoregroup by s_id
)a on stu.s_id = a.s_id

6 查询"李"姓老师的数量

--查询"李"姓老师的数量
select count(t_id) as count_li from teacher
where t_name like '李%'

7 查询学过"张三"老师授课的同学的信息

--查询学过"张三"老师授课的同学的信息select s_id, s_name, s_birth, s_sex 
from student where s_id in(select s_id from scorewhere c_id in (select c.c_id from teacher t join course c on c.c_id = t.t_id and t_name = '张三')
)

8 查询没学过"张三"老师授课的同学的信息

--查询没学过"张三"老师授课的同学的信息select s_id, s_name, s_birth, s_sex 
from student
where s_id not in (select s_idfrom score where c_id in (--select c.c_id from teacher t,course c where t_name = '张三' and t.t_id = c.c_idselect c.c_id from teacher t join course c on t.t_id = c.c_id and t_name = '张三')
)

9 查询学过编号为"01"并且也学过编号为"02"的课程的同学的信息

--查询学过编号为"01"并且也学过编号为"02"的课程的同学的信息select s_id, s_name, s_birth, s_sex 
from student
where s_id in (select s_idfrom scorewhere c_id = 01and s_id in (select s_id from score where c_id = 02)
)

10 查询学过编号为"01"但是没有学过编号为"02"的课程的同学的信息

select s_id, s_name, s_birth, s_sex 
from student where s_id in(select s_idfrom scorewhere c_id = 1--where s_id in (--      select s_id from score where c_id = 1--)and s_id not in (select s_id from score where c_id = 2)
)

11 查询没有学全所有课程的同学的信息

--查询没有学全所有课程的同学的信息select s_id, s_name, s_birth, s_sex 
from student
where s_id in (select s_idfrom scoregroup by s_id having count(c_id) != (select count(*) from course)
)

12 查询至少有一门课与学号为"01"的同学所学相同的同学的信息

--查询至少有一门课与学号为"01"的同学所学相同的同学的信息select s_id, s_name, s_birth, s_sex 
from student
where s_id in (select distinct s_idfrom scorewhere c_id in(select c_id from score where s_id = 1)
) and s_id != 1

13 查询和"01"号的同学学习的课程完全相同的其他同学的信息

--查询和"01"号的同学学习的课程完全相同的其他同学的信息
with data as (select distinct s_id,listagg(c_id,',') within group(order by c_id) over(partition by s_id) as cid_list
from score)select s_id, s_name, s_birth, s_sex 
from student
where s_id in (select s_id from datawhere cid_list in (select cid_list from data where s_id = 1) and s_id != 1
)

image.png

--查询和"01"号的同学学习的课程完全相同的其他同学的信息
select s_id, s_name, s_birth, s_sex 
from student
where s_id in(select s_id--, c_id, s_scorefrom score sinner join (select c_id from score where s_id = 1)a on a.c_id = s.c_idwhere s_id != 1group by s_idhaving count(*) = (select count(*) from score where s_id = 1)
)

14 查询没学过"张三"老师讲授的任一门课程的学生姓名

--查询没学过"张三"老师讲授的任一门课程的学生姓名select stu.s_id, stu.s_name, a.c_id
from student stu
join (select s_id, c_id, s_score from scorewhere c_id not in (select c.c_idfrom teacher tjoin course con t.t_id = c.c_id and t.t_name = '张三')
)a on a.s_id = stu.s_id
-- 没学过 -> 首先想到 排除学过的select * from student where s_id not in(select distinct s_id from score where c_id in(select c_id from course where t_id in(select t_id from teacher where t_name = '张三'   ))
)

15 查询两门及其以上不及格课程的同学的学号,姓名及其平均成绩

--查询两门及其以上不及格课程的同学的学号,姓名及其平均成绩with data as (
select s_id, c_id, s_score ,avg(s_score) over(partition by s_id) as avg_score
from score)select stu.s_id, stu.s_name, avg_score
from student stu
join (
select s_id,avg_score
from data
group by s_id,avg_score
having sum(case when s_score < 60 then 1 else 0 end) >= 2
)a on stu.s_id = a.s_id

16 检索"01"课程分数小于60,按分数降序排列的学生信息

select stu.s_id, s_name, s_birth, s_sex ,a.s_score
from student stu
join (
select s_id,s_score from score
where c_id = 1 and s_score < 60
)a on stu.s_id = a.s_id
order by a.s_score desc

17 按平均成绩从高到低显示所有学生的所有课程的成绩以及平均成绩

--按平均成绩从高到低显示所有学生的所有课程的成绩以及平均成绩
with data as (
select *
from (select s_id, c_id, s_score,avg(s_score) over(partition by s_id) as avg_score from score) 
pivot(max(s_score)for c_id in(1 as 数学,2 as 语文,3 as 英语)
)
)select d.*,stu.s_name
from data d
join student stu on stu.s_id = d.s_id

image.png

18 查询各科成绩最高分、最低分和平均分,以如下形式显示

--查询各科成绩最高分、最低分和平均分,以如下形式显示:
--课程ID,课程name,最高分,最低分,平均分,及格率,中等率,优良率,优秀率
--– 及格为>=60,中等为:70-80,优良为:80-90,优秀为:>=90select c_id, max(s_score ) as max_score, min(s_score ) as min_score, round(avg(s_score ),2) as avg_score, concat(round((sum(case when s_score >= 60 then 1 else 0 end) / count(*)) * 100,2),'%') as jg, concat(round((sum(case when s_score >= 70 and s_score < 80 then 1 else 0 end) / count(*)) * 100,2),'%') as zd , concat(round((sum(case when s_score >= 80 and s_score < 90 then 1 else 0 end) / count(*)) * 100,2),'%') as yl , concat(round((sum(case when s_score >= 90 then 1 else 0 end) / count(*)) * 100,2),'%') as yx 
from score
group by c_id

image.png

19 按各科成绩进行排序,并显示排名

select s.s_id, s.c_id,c.c_name, s.s_score ,rank() over(partition by s.c_id order by s.s_score desc) as rank
from score s
join student stu on s.s_id = stu.s_id
join course c on s.c_id = c.c_id
order by s.s_id,c.c_name,rank

20 查询学生的总成绩并进行排名

--查询学生的总成绩并进行排名
with data as (
select s_id, c_id, s_score ,sum(s_score) over(partition by s_id) as sum_score
from score
order by sum_score desc
)
select data.*,stu.s_name,rank() over(order by sum_score desc)  as rank
from data 
join student stu on stu.s_id = data.s_id
order by rank

21 查询不同老师所教不同课程平均分从高到低显示

--查询不同老师所教不同课程平均分从高到低显示select c.t_id,s.c_id,round(avg(s_score ),2) as avg_score
from course c
join score s on c.c_id = s.c_id
group by c.t_id,s.c_id
order by avg_score desc

22 查询所有课程的成绩第2名到第3名的学生信息及该课程成绩

--查询所有课程的成绩第2名到第3名的学生信息及该课程成绩
with data as (
select s_id, c_id, s_score,rank() over(partition by c_id order by s_score desc) as rankfrom score)select stu.*,data.c_id,data.s_score
from data 
join student stu on stu.s_id = data.s_id and rank between 2 and 3

23 统计各科成绩各分数段人数:课程编号,课程名称,[100-85),[85-70),[70-60),[0-60)及所占百分比

--统计各科成绩各分数段人数:课程编号,课程名称,[100-85),[85-70),[70-60),[0-60)及所占百分比
with socre_s as (
select s_id, c_id, s_score,count(s_id) over(partition by c_id) as c_s_count,case when s_score > 85 and s_score <= 100 then '[100-85)'when s_score > 70 and s_score <= 85 then '[85-70)'when s_score > 60 and s_score <= 70 then '[70-60)'when s_score >= 0 and s_score < 60 then '[0-60)'end as score_djfrom score)select s_id, c_id,score_dj,concat(round((count(s_id) / c_s_count),2) * 100,'%') as pre_score
from socre_s
group by s_id, c_id,score_dj,c_s_count

image.png

24 查询学生平均成绩及其名次

select s.s_id, c_id, s_score ,s_name,avg(s_score) over(partition by s.s_id) as avg_score,rank() over(partition by c_id order by s_score desc)
from score s
join student stu
on stu.s_id = s.s_id

25 查询各科成绩前三名的记录

with data1 as (
select s_id, c_id, s_score ,rank() over(partition by c_id order by s_score desc) as rank
from score
)select s.s_id, s.s_name,c.c_id, c.c_name, c.t_id ,d.s_score
from course c
join data1 d on c.c_id = d.c_id and d.rank <= 3
join student s on s.s_id = d.s_id

image.png

--感觉写的很奇怪,平常都不这么用select c.c_id,c.c_name,s.s_id,s.s_name,s_score
from (select *from score scwhere (select count(*)from score sc1where sc.c_id = sc1.c_idand sc.s_score < sc1.s_score) < 3
)
t1
inner join student s on t1.s_id = s.s_id 
inner join course c on t1.c_id = c.c_id 
order by c.c_id,s_score desc

26 查询每门课程被选修的学生数

select c.c_id, c_name, t_id ,count_s
from course c
join (
select count(s_id) as count_s, c_id
from score
group by c_id
) a
on c.c_id = a.c_id

27 查询出只有两门课程的全部学生的学号和姓名

select s_id, s_name, s_birth, s_sex 
from student
where s_id in (
select s_id
from score
group by s_id
having count(c_id) = 2
)

28 查询男生、女生人数

select  s_sex ,count(s_id ) as count
from student
group by s_sex

29 查询名字中含有"风"字的学生信息

select s_id, s_name, s_birth, s_sex 
from student
where s_name like '%风%'

30 统计同姓的人员名单,打印 姓 人数 姓名

--统计同姓的人员名单,打印 姓 人数 姓名
select substr(s_name,0,1) as first_name, s_name,count(s_name) over(partition by substr(s_name,0,1)) as first_name_count
from student

image.png

31 查询1990年出生的学生名单

select s_id, s_name, s_birth, s_sex 
from student
--where to_char(s_birth,'yyyy') = 1990
where extract(year from s_birth) = 1990

32 查询每门课程的平均成绩,结果按平均成绩降序排列,平均成绩相同时,按课程编号升序排列

--select c_id, avg(s_score) as avg_score
from score 
group by c_id
order by avg(s_score) desc,c_id

33 查询平均成绩大于等于85的所有学生的学号、姓名和平均成绩

select stu.s_id, s_name, avg_score
from student stu
join 
(select s_id, avg(s_score) as avg_score 
from score
group by s_id
having avg(s_score) >= 85) s
on s.s_id = stu.s_id

34 查询课程名称为"数学",且分数低于60的学生姓名和分数

select stu.s_name, s.s_score 
from score s
join student stu
on s.s_id = stu.s_id
where c_id in (select c_id from course where c_name = '数学'
)and s.s_score  < 60

35 查询所有学生的课程及分数情况

Result1 group
select stu.s_id, s_name, s_birth, s_sex ,sum(case when s.c_id = 1 then s.s_score end) as 数学,sum(case when s.c_id = 2 then s.s_score end) as 语文,sum(case when s.c_id = 3 then s.s_score end) as 英语
from student stu
join score s on stu.s_id = s.s_id
join course c on s.c_id = c.c_id
group by stu.s_id, s_name, s_birth, s_sex 
Result2 pivot
with data as (
SELECT *
FROM scorePIVOT (MAX(s_score)FOR c_id IN (1 as 数学, 2 as 语文, 3 as 英语))
)select s.s_name, s.s_birth, s.s_sex ,d.*
from student s
join data d
on s.s_id  = d.s_id

image.png

select stu.s_id, s_name, s_birth, s_sex , coalesce(a.s_score,0) as  数学, coalesce(b.s_score,1) as  语文, coalesce(c.s_score,2) as  英语
from student stu
left join (select s_id, c_id, s_score from score where c_id = 1) a on a.s_id = stu.s_id
left join (select s_id, c_id, s_score from score where c_id = 2) b on b.s_id = stu.s_id
left join (select s_id, c_id, s_score from score where c_id = 3) c on c.s_id = stu.s_id

36 查询任何一门课程成绩在70分以上的学生姓名、课程名称和分数

--查询任何一门课程成绩在70分以上的学生姓名、课程名称和分数(任何的理解不同)select s_name, c.c_name  ,s.s_score
from student stu
join (select s_id, c_id, s_score ,max(s_score) over(partition by s_id) as max_scorefrom score) s
on stu.s_id = s.s_id
and s.max_score > 70 
join course c
on s.c_id = c.c_id

image.png

37 查询课程不及格的学生

--
select stu.s_id, s_name, s_birth, s_sex ,s.s_score
from student stu
join score s
on stu.s_id = s.s_id
and s.s_score < 60 

38 查询课程编号为01且课程成绩在80分以上的学生的学号和姓名


select s_id, s_name, s_birth, s_sex 
from student s
where s_id in(select s_idfrom scorewhere c_id = 1 and s_score >= 80
)

39 查询每门课程的人数

select c.c_id, c_name, t_id ,count_s 
from course c
join(select c_id,count(s_id) as count_sfrom scoregroup by c_id
)a
on c.c_id = a.c_id

40 查询选修"张三"老师所授课程的学生中,成绩最高的学生信息及其成绩

with cid as (
select c.c_id 
from course c
join teacher t
on c.t_id = t.t_id 
and t.t_name = '张三')
select * from (
select s.*,stu.s_name,rank() over(order by s_score desc) as rank
from score s
join cid on cid.c_id = s.c_id
join student stu on stu.s_id = s.s_id
) where rank = 1

image.png

41 查询不同课程成绩相同的学生的学生编号、课程编号、学生成绩

select s.s_id,stu.s_name,s.c_id,s.s_score 
from score s
join  (select s_idfrom scoregroup by s_id,s_score having count(c_id  ) > 1
) a
on s.s_id = a.s_id
join student stu
on stu.s_id = s.s_id
order by s.s_id,s.c_id--严谨一点
select a.s_id,s.s_name,a.c_id,a.s_score
from (selects_id,c_id,s_score,count(c_id) over(partition by s_id,s_score) as count_scorefrom score
)a
join student s
on s.s_id = a.s_id
and count_score > 1

image.png

image.png

select * from score where s_score in(select s_scorefrom score group by s_score having count(1) > 1
)

42 统计每门课程的前几名

select a.c_id ,c_name ,a.s_id ,s_name ,s_score 
from (
selects_id ,c_id ,s_score ,rank() over(partition by c_id order by s_score desc) as rank,row_number() over(partition by c_id order by s_score desc) as rn
from score) a
join student s
on a.rank <=3
and s.s_id = a.s_id
join course c
on c.c_id = a.c_id
order by a.c_id ,c_name ,a.s_id ,s_name ,s_score 

43 统计课程的选课人数,> 5 才统计

--要求输出课程号和选修人数,查询结果按人数降序排列,若人数相同,按课程号升序排列
selectc_id,count(s_id ) as count_s
from score
group by c_id 
having count(s_id ) > 5
order by count(s_id ) desc,c_id

44 查询选修了2门课的sid

selects_id
from score
group by s_id 
having count(c_id ) >= 2

45 查询选修了全部课程的学生信息


select * from student
where s_id in (
selects_id
from score
group by s_id 
having count(c_id ) = (select count(c_id ) from course)
)

46 求学生周岁

selects_name ,s_birth ,trunc(MONTHS_BETWEEN(SYSDATE, s_birth ) / 12)from student

image.png

47 本周过生日的同学

selectto_char(trunc(sysdate,'IW'),'yyyy-mm-dd')  this_monday,to_char(trunc(sysdate,'IW') + 6,'yyyy-mm-dd')  this_sunday,to_char(trunc(next_day((sysdate),1)) ,'yyyy-mm-dd') next_fir_day_sun,to_char(trunc(next_day((sysdate),'星期日')),'yyyy-mm-dd')  next_sunday
from dual

image.png

48 下周过生日的同学

select*
from student
where s_birth between (trunc(sysdate,'IW') + 7) and (trunc(sysdate,'IW') + 13)

image.png

49 查询本月过生日的同学

select * from student
where extract(month from s_birth) = extract(month from sysdate)

image.png

50 查询12月份过生日的同学

select * from student
where to_char(s_birth ,'mm') = '12'

image.png

本文来自互联网用户投稿,该文观点仅代表作者本人,不代表本站立场。本站仅提供信息存储空间服务,不拥有所有权,不承担相关法律责任。如若转载,请注明出处:http://www.hqwc.cn/news/418656.html

如若内容造成侵权/违法违规/事实不符,请联系编程知识网进行投诉反馈email:809451989@qq.com,一经查实,立即删除!

相关文章

VS Code + Python + Selenium 自动化测试基础-01

VS Code Python Selenium 自动化测试基础-01 让我们来讲一个故事为什么要写自动化开发前的准备工作牛刀小试开常用的web DriverAPI-定位元素id定位&#xff1a;find_element_by_id()name 定位&#xff1a;find_element_by_name()class 定位&#xff1a;find_element_by_class…

redis远程连接不上解决办法

问题描述&#xff1a; redis远程服务端运行在192.168.3.90计算机上&#xff0c;客户端计算机&#xff08;ip:192.168.3.110&#xff09;通过redsi-cli.exe客户端工具连接时&#xff0c;没有反应&#xff0c;连接不上。 如图所示&#xff1a; 解决步骤&#xff1a; 步骤一&…

Civil 3D安装教程,免费使用,带安装包和工具,一分钟轻松搞的安装

前言 Civil 3D是一款面向基础设施行业的建筑信息模型&#xff08;BIM&#xff09;解决方案。它为基础设施行业的各类技术人员提供了强大的设计、分析以及文档编制功能&#xff0c;广泛适用于勘察测绘、岩土工程、交通运输、水利水电、市政给排水、城市规划和总图设计等众多领域…

【高等数学之极限】

一、引言 我们先思考一下&#xff0c;上面三个表达式&#xff0c;是否可以将极限值直接代入求值&#xff0c;我们在计算之前需要先分析一下&#xff0c;如果将极限值代入&#xff0c;那么表达式将会变成什么形式? 经过上面的分析&#xff0c;我们发现第一个式子可以直接带入&a…

Python 中多线程与多处理之间的区别

一、说明 在本文中&#xff0c;我们将学习 Python 中多线程和多处理的内容、原因和方式。在我们深入研究代码之前&#xff0c;让我们了解这些术语的含义。 二、基本术语和概念 程序是一个可执行文件&#xff0c;它由一组执行某些任务的指令组成&#xff0c;通常存储在计算机的…

BGP Origin 属性控制选路试验

一、拓朴图&#xff1a; 二、配置步骤&#xff1a; 1、配置 IP 2、配置 IGP&#xff0c;我们这里用了静态&#xff0c;互相宣告了对端接口和 Loopback 0 3、配置 BGP 4、在 R1 上通过 BGP 宣告 1.1.1.1&#xff0c;查看 R2 的路由&#xff0c;发现两条 1.1.1.1 的路由&#x…

解决小程序字体在最左上角问题

问题如下 原因&#xff1a; 出现这种现象的原因是项目默认开启了Skyline渲染模式&#xff0c;因为Skyline渲染模式不支持原生导航栏&#xff0c;所以在json文件中设置的导航栏失效&#xff0c;文字就会向上移动&#xff0c;如果想要使用原生的导航栏&#xff0c;可以将app.jso…

App 测试工具大全,收藏这篇就够了

随着移动互联网的高速发展&#xff0c;App应用非常火&#xff0c;测试工程师也会接触到各种app应用。除了人工测试之外&#xff0c;也可以通过一些测试工具来提高我们的测试效率&#xff0c;以下对于我用过或听过的app测试工具做了一个统一整理&#xff0c;欢迎补充。 一、APP自…

SpringMVC简介和SpringMVC的HelloWorld

一、SpringMVC简介 1、什么是MVC MVC是一种软件架构的思想&#xff0c;将软件按照模型、视图、控制器来划分 M&#xff1a;Model&#xff0c;模型层&#xff0c;指工程中的JavaBean&#xff0c;作用是处理数据 JavaBean分为两类&#xff1a; 一类称为实体类Bean&#xff1a…

【跳槽面试】Redis中分布式锁的实现

分布式锁常见的三种实现方式&#xff1a; 数据库乐观锁&#xff1b;基于Redis的分布式锁&#xff1b;基于ZooKeeper的分布式锁。 本地面试考点是&#xff0c;你对Redis使用熟悉吗&#xff1f;Redis中是如何实现分布式锁的。 在Redis中&#xff0c;分布式锁的实现主要依赖于R…

C++函数对象-函数包装器-(std::bad_function_call)

任何定义了函数调用操作符的对象都是函数对象。C 支持创建、操作新的函数对象&#xff0c;同时也提供了许多内置的函数对象。 函数包装器 std::function 提供存储任意类型函数对象的支持。 用空的 std::function 时抛出的异常 std::bad_function_call class bad_function_cal…

MSSQL-识别扩展extended event(扩展事件)中的时间单位

经常使用sqlserver extended event(扩展事件)&#xff0c;但是总是忘记扩展事件使用的时间单位&#xff0c;不确定它们是 秒、毫秒、还是微秒&#xff1f; 以下下代码能够从 相关DMV中提取description字段内容来识别时间单位&#xff1a; SELECT [p].[name] [package_name],[o…