1.题目描述

2.解题思路
刚看到这个题目的时候，感觉说的有点啰嗦，其实不难发现，这个题目和之前的给你多少钱，什么2元，5元的，给你一个数字，让你算各种钱币有多少张。无非就是从小到大进行判断，首先判断给定的数字，能容纳多少个最大的，然后依次减少。
3.代码实现

class Solution:def intToRoman(self, num: int) -> str:str1 = ""while num != 0:print("num",num)if int(num / 1000):num1 = int(num / 1000)for i in range(0, num1):str1 = str1 + "M"num = num - num1 * 1000elif int(num / 900):num1 = int(num / 900)for i in range(0, num1):str1 = str1 + "CM"num = num - num1 * 900elif int(num / 500):num1 = int(num / 500)for i in range(0, num1):str1 = str1 + "D"num = num - num1 * 500elif int(num / 400):num1 = int(num / 400)for i in range(0, num1):str1 = str1 + "CD"num = num - num1 * 400elif int(num / 100):num1 = int(num / 100)for i in range(0, num1):str1 = str1 + "C"num = num - num1 * 100elif int(num / 90):num1 = int(num / 90)for i in range(0, num1):str1 = str1 + "XC"num = num - num1 * 90elif int(num / 50):num1 = int(num / 50)for i in range(0, num1):str1 = str1 + "L"num = num - num1 * 50elif int(num / 40):num1 = int(num / 40)for i in range(0, num1):str1 = str1 + "XL"num = num - num1 * 40elif int(num / 10):num1 = int(num / 10)for i in range(0, num1):str1 = str1 + "X"num = num - num1 * 10elif int(num / 9):num1 = int(num / 9)for i in range(0, num1):str1 = str1 + "IX"num = num - num1 * 9elif int(num / 5):num1 = int(num / 5)for i in range(0, num1):str1 = str1 + "V"num = num - num1 * 5elif int(num / 4):num1 = int(num / 4)for i in range(0, num1):str1 = str1 + "IV"num = num - num1 * 4elif int(num / 1):num1 = int(num / 1)for i in range(0, num1):str1 = str1 + "I"num = num - num1 * 1return str1