题干

C++实现

#include <iostream>
#include <stdio.h>
#include <algorithm>
using namespace std;int dp[1002][1002];int main() {int n,m;char s1[1001];char s2[1001];scanf("%d%d",&n,&m);scanf("%s%s",s1,s2);//dp[i][j]是s1的前i个元素，s2的前j个元素的最大公共长度for(int j = 0; j<=m; j++) {dp[0][j] = 0;}for(int i = 0; i<=n; ++i) {dp[i][0] = 0;}for(int i = 1; i<=n; i++) {for(int j= 1; j<=m; ++j) {if(s1[i-1] == s2[j-1]) {dp[i][j] = dp[i-1][j-1] + 1;} else {dp[i][j] = max(dp[i][j-1],dp[i-1][j]);}}}printf("%d\n",dp[n][m]);return 0;
}