问题描述:
题解:
#include <bits/stdc++.h>
using namespace std;
using ll = long long;
const int N = 105;
const ll p = 1e6 + 7;
ll a[N], dp[N][N];int main()
{int n, m; cin >> n >> m;for(int i = 1; i <= n; i++)cin >> a[i];dp[0][0] = 1;for(int i = 1; i <= n; i++){for(int j = 0; j <= m; j++){for(int k = 0; k <= a[i] && k <= j; k++)dp[i][j] = (dp[i][j] + dp[i - 1][j - k]) % p; // k表示个数}} cout << dp[n][m] << '\n';return 0;
}