2.13 已知f(x)=(|x+1|-|x-1|)/2+sinx,g(x)=(|x+3|-|x-3|)/2+cosx,求下列超定方程组的最小二乘解

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import numpy as np  def f(x):  return (abs(x + 1) - abs(x - 1)) / 2 + np.sin(x)  def g(x):  return (abs(x + 3) - abs(x - 3)) / 2 + np.cos(x)  # 假设我们有一些初始猜测值（这里只是随机选择的）  
x1_guess = 0.5  
x2_guess = 1.0  
y1_guess = 0.2  
y2_guess = 0.3  # 定义方程组矩阵A和向量b  
def create_system(x1, x2, y1, y2):  A = np.array([  [0, 0, 3*f(y1), 4*g(y2)],  [2, 0, 2*f(y1), 6*g(y2)],  [f(x1), 3*g(x2), -1, 0],  [4*f(x1), g(x2), 0, -1],  [1, -3, 0, -10*f(y1)],  ])  b = np.array([-1, -2, -3, -1, 2])  return A, b  # 使用初始猜测值来创建方程组  
A, b = create_system(x1_guess, x2_guess, y1_guess, y2_guess)  # 使用numpy.linalg.lstsq求解最小二乘解  
sol, residuals, rank, s = np.linalg.lstsq(A, b, rcond=None)  print("最小二乘解：")  
print("x1 =", sol[0])  
print("x2 =", sol[1])  
print("y1 =", sol[2])  
print("y2 =", sol[3])  
print("残差平方和：", residuals[0])print("学号：2023310143004")