2024.12.16 周一
Q1. 1000
Monocarp is playing yet another computer game. And yet again, his character is killing some monsters. There are $n$ monsters, numbered from $1$ to $n$, and the $i$-th of them has $a_i$ health points initially.
Monocarp's character has an ability that deals $k$ damage to the monster with the highest current health. If there are several of them, the one with the smaller index is chosen. If a monster's health becomes less than or equal to $0$ after Monocarp uses his ability, then it dies.
Monocarp uses his ability until all monsters die. Your task is to determine the order in which monsters will die.
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昨天数据结构考试+第二题被位运算加构造卡了，就润了，所以就一道题..
A1.
- 在原有的基础上考虑加速加速操作。发现最终顺序和模 $k$ 之后大小有关。按照这种意义排序即可。
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A1.
#include <bits/stdc++.h>
#define int long long //
#define endl '\n' // 交互/调试 关
using namespace std;
#define bug(BUG) cout << "bug:# " << (BUG) << endl
#define bug2(BUG1, BUG2) cout << "bug:# " << (BUG1) << " " << (BUG2) << endl
#define bug3(BUG1, BUG2, BUG3) cout << "bug:# " << (BUG1) << ' ' << (BUG2) << ' ' << (BUG3) << endl
void _();
signed main()
{ios::sync_with_stdio(0), cin.tie(0), cout.tie(0);cout << fixed << setprecision(6);int T = 1;cin >> T;while (T--)_();return 0;
}void _()
{int n, k;cin >> n >> k;struct Node{/* data */int x, i;};vector<Node> a(n);for (int i = 0; i < n; i++){int t;cin >> t;// a[i].x = k - t % k;a[i].x = t % k;a[i].x = !a[i].x ? k : a[i].x;a[i].i = i;// bug2(i + 1, a[i].x);}sort(a.begin(), a.end(), [](Node &a, Node &b){ return a.x - b.x ? a.x > b.x : a.i < b.i; });for (auto [x, i] : a)cout<< i + 1 << ' ';cout << endl;
}
