1. 示例代码：
/* 用递归调用求 Ackerman(m, n) 的值 */#include <stdio.h>int Ackerman(int m, int n);int main(void)
{int m = 0, n = 0;printf("Please input m and n: ");scanf_s("%d%d", &m, &n);printf("Ackerman(%d, %d) = %d\n", m, n, Ackerman(m, n));return 0;
}int Ackerman(int m, int n)
{int z = 0;if (m == 0) {z = n + 1;} else if (n == 0) {z = Ackerman(m - 1, 1);} else {z = Ackerman(m - 1, Ackerman(m, n - 1));}return z;
}2. 输出示例：
