第一组表单信息

1、查询每个部门的所属员工

mysql> SELECT name,GROUP_CONCAT(ename) persons-> FROM dept3 d-> LEFT JOIN emp3 e-> ON d.deptno = e.dept_id-> GROUP BY d.deptno-> UNION -> SELECT name,GROUP_CONCAT(ename) persons-> FROM dept3 d-> RIGHT JOIN emp3 e-> ON d.deptno = e.dept_id-> GROUP BY e.dept_id-> ;

2、查询研发部门的所属员工

mysql> select name,group_concat(ename)-> from dept3 d,emp3 e-> where name = '研发部' and d.deptno=e.dept_id-> group by name;

3、查询研发部和销售部的所属员工

mysql> select name,group_concat(ename)-> from dept3 d,emp3 e-> where (name='研发部' or name='销售部')-> and d.deptno=e.dept_id-> group by name;

 

4、查询每个部门的员工数,并升序排序

mysql> SELECT name,COUNT(ename) persons-> FROM dept3 d-> LEFT JOIN emp3 e-> ON d.deptno = e.dept_id-> GROUP BY d.deptno-> -> UNION-> -> SELECT name,COUNT(ename) persons-> FROM dept3 d-> RIGHT JOIN emp3 e-> ON d.deptno = e.dept_id-> GROUP BY e.dept_id-> ORDER BY persons-> ;

5、查询人数大于等于3的部门，并按照人数降序排序

mysql> SELECT name,COUNT(ename) persons-> FROM dept3 d-> LEFT JOIN emp3 e-> ON d.deptno = e.dept_id-> GROUP BY d.deptno-> HAVING persons > 3->    -> UNION->      -> SELECT name,COUNT(ename) persons-> FROM dept3 d-> RIGHT JOIN emp3 e-> ON d.deptno = e.dept_id-> GROUP BY e.dept_id-> HAVING persons > 3-> ORDER BY persons-> ;

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第二组表单信息

1.找出销售部门中年纪最大的员工的姓名

mysql> select name from dept,emp-> where dept1=dept2-> and age=(select max(age) from emp where dept_name='销售')-> ;

2.求财务部门最低工资的员工姓名

mysql> select name from dept,emp-> where dept1=dept2-> and incoming=(select min(incoming) from emp where dept_name='财务')-> ;

 

3.列出每个部门收入总和高于9000的部门名称

mysql> SELECT dept.dept_name,SUM(emp.incoming) AS total-> FROM dept-> LEFT JOIN emp -> ON dept.dept1 = emp.dept2-> GROUP BY dept.dept_name-> HAVING total > 9000-> ;

4.求工资在7500到8500元之间，年龄最大的人的姓名及部门

mysql> SELECT d.dept_name,e.name-> FROM dept d-> LEFT JOIN emp e -> ON d.dept1 = e.dept2-> Where incoming Between 7500 And 8500-> Order By e.age Desc-> Limit 1-> ;

5.找出销售部门收入最低的员工入职时间

mysql> SELECT e.worktime_start-> FROM dept d-> LEFT JOIN emp e -> ON d.dept1 = e.dept2-> Where d.dept_name='销售'-> Order By e.incoming-> Limit 1-> ;

6.财务部门收入超过2000元的员工姓名

mysql> SELECT e.name-> FROM dept d-> LEFT JOIN emp e -> ON d.dept1 = e.dept2-> Where d.dept_name='财务'-> And incoming > 2000-> ;

  

7.列出每个部门的平均收入及部门名称

mysql> SELECT d.dept_name,avg(e.incoming)-> FROM dept d-> LEFT JOIN emp e -> ON d.dept1 = e.dept2-> Group By d.dept_name-> ;

8.IT技术部入职员工的员工号

mysql> SELECT sid-> FROM dept d-> LEFT JOIN emp e -> ON d.dept1 = e.dept2-> where d.dept_name='IT技术'-> ;

9.财务部门的收入总和；

mysql> SELECT sum(e.incoming) total-> FROM dept d-> LEFT JOIN emp e -> ON d.dept1 = e.dept2-> Group By d.dept_name-> Having d.dept_name='财务'-> ;

  

10.先按部门号大小排序，再依据入职时间由早到晚排序员工信息表

mysql> SELECT *-> FROM dept d-> LEFT JOIN emp e -> ON d.dept1 = e.dept2-> Order By dept1 Desc,worktime_start Asc-> ;

11.找出哪个部门还没有员工入职

mysql> SELECT dept_name-> FROM dept d-> LEFT JOIN emp e -> ON d.dept1 = e.dept2-> Where e.name Is Null -> ;

12.列出部门员工收入大于7000的部门编号，部门名称；

在MySQL的ONLY_FULL_GROUP_BY模式下，所有非聚合的SELECT列都必须包含在GROUP BY子句中，并且SELECT列表中的列必须对GROUP BY子句中的列有功能上的依赖关系。

mysql> SELECT dept1 As dept_num,d.dept_name,Max(e.incoming)-> FROM dept d-> LEFT JOIN emp e -> ON d.dept1 = e.dept2-> Group By d.dept1,d.dept_name-> Having Max(incoming) > 7000-> ;

 

13.列出每一个部门的员工总收入及部门名称；

mysql> SELECT dept_name,Sum(e.incoming)-> FROM dept d-> LEFT JOIN emp e -> ON d.dept1 = e.dept2-> Group By d.dept1,d.dept_name-> ;

14.列出每一个部门中年纪最大的员工姓名，部门名称；

子查询
mysql> SELECT d.dept_name, e.name, e.age-> FROM dept d-> LEFT JOIN emp e ON d.dept1 = e.dept2->      JOIN (->            SELECT dept2, MAX(age) AS max_age->            FROM emp->            GROUP BY dept2->           ) AS m->       ON e.dept2 = m.dept2 AND e.age = m.max_age-> ;

15.求李四的收入及部门名称

mysql> SELECT dept_name,name,incoming-> FROM dept d-> LEFT JOIN emp e -> ON d.dept1 = e.dept2-> Having name='李四'-> ;

16.列出每个部门中收入最高的员工姓名，部门名称，收入，并按照收入降序

mysql> SELECT dept_name,name,incoming-> FROM dept d-> LEFT JOIN emp e -> ON d.dept1 = e.dept2-> Where e.incoming Is Null -> Or (e.incoming=(Select Max(incoming) ->                 From emp->                 Where dept2=e.dept2 ->                )->    )-> ;

17.列出部门员工数大于1个的部门名称

mysql> SELECT dept_name-> FROM dept-> WHERE dept1 IN (->     SELECT dept2->     FROM emp->     GROUP BY dept2->     HAVING COUNT(*) > 1-> );

  

19.查找张三所在的部门名称

mysql> SELECT dept_name-> FROM dept-> WHERE dept1 IN (->     SELECT dept2->     FROM emp->     Where name='张三'-> );