数据结构与算法编程题50-编程知识

数据结构与算法编程题50

假设不带权有向图采用邻接矩阵G存储，设计实现以下功能的算法。
（1）求出图中每个顶点的出度。
（2）求出图中出度为0的顶点数。
（3）求出图中每个顶点的入度。

//参考博客：https://blog.csdn.net/qq_54162207/article/details/117414707#include <iostream>
using namespace std;#define Maxsize 100
#define VertexmMaxNum 20
#define ERROR  0
#define OK     1
typedef string VertexType;
typedef int  EdgeType;typedef struct Graph   //无向图
{VertexType vex[VertexmMaxNum];EdgeType edge[VertexmMaxNum][VertexmMaxNum];int vexnum;     //顶点数int edgenum;  //边数
}Graph;//确定某顶点在G中的位置下标
int locateVex(Graph& G, VertexType v)
{for (int i = 0; i < G.vexnum; i++){if (v == G.vex[i]) return i;}return -1;
}void CreateDG(Graph& G)
{int i = 0, j = 0;cout << "请输入有向图的顶点数和边数:";cin >> G.vexnum >> G.edgenum;cout << "请输入顶点:";for (i = 0; i < G.vexnum; i++){cin >> G.vex[i];}for (i = 0; i < G.vexnum; i++){for (j = 0; j < G.vexnum; j++)G.edge[i][j] = 0;}for (int k = 0; k < G.edgenum; k++){cout << "请输入第" << k + 1 << "条边：";VertexType v1, v2;cin >> v1 >> v2;int i = locateVex(G, v1);int j = locateVex(G, v2);G.edge[i][j] = 1;}
}/*--------打印图的邻接矩阵-----------*/
void PrintfUGraph(Graph G) {//将图的邻接矩阵输出在控制台上for (int i = 0; i < G.vexnum; i++) {cout << "v" << i + 1 << ":";for (int j = 0; j < G.vexnum; j++)cout << G.edge[i][j] << " ";cout << endl;}
}
//2.假设不带权有向图采用邻接矩阵G存储，设计实现以下功能的算法。
//（1）求出图中每个顶点的出度。
//（2）求出图中出度为0的顶点数。
//（3）求出图中每个顶点的入度。
//-------------------------核心代码-------------------------//
void count_chudu(Graph G)
{int count = 0;for (int i = 0; i < G.vexnum; i++){count = 0;for (int j = 0; j < G.vexnum; j++){if (G.edge[i][j] == 1)count++;}cout << G.vex[i] << "的出度的数量为:" << count << endl;}
}void count_chudu_zero(Graph G)
{int zero_count = 0;int count = 0;for (int i = 0; i < G.vexnum; i++){zero_count = 0;for (int j = 0; j < G.vexnum; j++){if (G.edge[i][j] == 0)zero_count++;}if (zero_count == G.vexnum)count++;}cout <<"出度为0的顶点数:" << count << endl;
}void count_rudu(Graph G)
{int count = 0;for (int i = 0; i < G.vexnum; i++){count = 0;for (int j = 0; j < G.vexnum; j++){if (G.edge[j][i] == 1)count++;}cout << G.vex[i] << "的入度的数量为:" << count << endl;}
}
//-------------------------核心代码-------------------------//
//顶点信息
//v1 v2 v3
//边信息
/*
v1 v2
v1 v3
v2 v3
*/
int main(void)
{Graph G;CreateDG(G);  //不带权有向图PrintfUGraph(G);cout << "--------------------求出图中每个顶点的出度--------------------" << endl;count_chudu(G);cout << "--------------------求出图中出度为0的顶点数--------------------" << endl;count_chudu_zero(G);cout << "--------------------求出图中每个顶点的入度--------------------" << endl;count_rudu(G);return 0;
}