【JS逆向一】逆向某站的加密参数算法--仅供学习参考-编程知识

逆向日期：2024.02.06

使用工具：Node.js

文章全程已做去敏处理！！！【需要做的可联系我】

可使用AES进行解密处理（直接解密即可）：在线AES加解密工具

1、打开某某网站(请使用文章开头的AES在线工具解密)：T9mpG48zIdYFB40hkjsQS4+N5rr4x4mSPHlx5EoT/+s=

2、点击右上角的登录按钮，账号随便11位即可，密码随便，验证码输入，点击登录后可在控制台的网络面板进行查看

3、ctrl+shift+F全局搜索【poaaword】，经过我七七八百天终于找到了，他在这里被加密，其中【W】参数位固定值，【l】参数为10位整数的时间戳，【a.data.password】为明文

4、我在控制台调用【K】加密函数，发现每次加密结果都不一样，要么是RSA加密，要么就是里面有时间戳，我们直接单步进【K】函数

5、通过【K】参数进来后，发现就在刚刚加密参数的下面，一大堆，好像是被拆散了，这种也看不出来是什么加密，直接扣他源代码就行

6、扣下来后直接调用运行，发现有报错，报错显示【f】参数未定义，我们去源代码瞅瞅

7、在源代码里发现【f】参数是一个key，但这也不能证明此网站的加密方法是RSA，也有可能是DES或AES，因为里面好像有时间戳，所有导致每次加密的结果都不一样，那我们直接把key复制到我们代码里

8、幺，成了，把key拿过来后，加密成功了，而且每次的加密结果都不一样，我们还差用【btoa】加密一下就欧克了，btoa是内置函数，可以直接调用，我们直接在代码里添加即可

9、看结果，加密三次都是不一样的结果，哎这就成了

【附上源码】

为防止二次编辑或对该网站的原创保护，只能将源代码进行混淆展示。

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_0x298ae8();_0x29b5c8=_0x181d13(_0x22f49b);for(_0x274b7e=_0x4b0073=0x23b0b^0x23b0b;_0x274b7e<=_0x29b5c8;++_0x274b7e)_0x4b0073=result['digits'][_0x274b7e]+_0x22f49b['digits'][_0x274b7e]*_0x375b2c+_0x4b0073,result['digits'][_0x274b7e]=_0x4b0073&0xffff,_0x4b0073>>>=0x502cc^0x502dc;result['digits'][0x1+_0x29b5c8]=_0x4b0073;_0x14dddd=_0x57a6b1(_0x14dddd,result);_0x14dddd["\u0069\u0073\u004e\u0065\u0067"]&&(_0x14dddd=_0x28a2f0(_0x14dddd,_0x402d89),--_0x27d8f7['digits'][_0x574137-_0x38e274-0x1]);}_0x14dddd=_0x579545(_0x14dddd,_0x5f5804);_0x27d8f7['isNeg']=_0xb919f9['isNeg']!=_0x3c50d3;_0xb919f9['isNeg']&&(_0x27d8f7=_0x3c50d3?_0x28a2f0(_0x27d8f7,_0x1eb173):_0x57a6b1(_0x27d8f7,_0x1eb173),_0x14e496=_0x579545(_0x14e496,_0x5f5804),_0x14dddd=_0x57a6b1(_0x14e496,_0x14dddd));0x0==_0x14dddd['digits'][0x0]&&(0x3d9c8^0x3d9c8)==_0x181d13(_0x14dddd)&&(_0x14dddd['isNeg']=!0x1);}_0xb919f9=[_0x27d8f7,_0x14dddd];this['mu']=_0xb919f9[0xf1b7e^0xf1b7e];this['bkplus1']=new 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this['modulo'](_0x274e57);}function _0x2c31c5(_0x51650d,_0x35df20){var _0x2314f2=new _0x298ae8();for(_0x2314f2['digits'][0x549dc^0x549dc]=0x1;;){0x0!=(_0x35df20["\u0064\u0069\u0067\u0069\u0074\u0073"][0xb7ac8^0xb7ac8]&0x1)&&(_0x2314f2=this['multiplyMod'](_0x2314f2,_0x51650d));_0x35df20=_0x579545(_0x35df20,0x1);if(0x0==_0x35df20['digits'][0x0]&&(0x73a12^0x73a12)==_0x181d13(_0x35df20))break;_0x51650d=this['multiplyMod'](_0x51650d,_0x51650d);}return _0x2314f2;}function _0x1968b6(_0x968739){this["\u0065"]=_0xf30f34('10001');this['d']=_0xf30f34("".split("").reverse().join(""));this["\u006d"]=_0xf30f34(_0x968739);this['chunkSize']=0x80;this['radix']=0x10;this['barrett']=new _0x425338(this['m']);}var _0x4c40b3,_0x205846,_0x1eb173;_0xfbf4e(0xc855c^0xc8548);(function(_0x160053){var _0x126518=new _0x298ae8();_0x126518['isNeg']=0x0>_0x160053;_0x160053=Math['abs'](_0x160053);for(var _0x9f3301=0x0;0x0<_0x160053;)_0x126518['digits'][_0x9f3301++]=_0x160053&0xffff,_0x160053>>=0x10;return 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