任务二：判断它能否构成三角形
#include <stdio.h>
int main()
{
double a, b, c;
scanf_s("%lf%lf%lf", &a, &b, &c);
if ((a + b > c) && (a + c > b) && (b + c > a))
printf("能构成三角形\n");
else
printf("不能构成三角形\n");
return 0;
}
任务三：
#include <stdio.h>
int main()
{
char ans1, ans2;
printf("每次课前认真预习、课后及时复习了没? (输入y或Y表示有，输入n或N表示没有) : ");
ans1 = getchar();
getchar();
printf("\n动手敲代码实践了没? (输入y或Y表示敲了，输入n或N表示木有敲) : ");
ans2 = getchar();
if ((ans1 == 'y' || ans1 == 'Y') && (ans2 == 'y' || ans2 == 'Y'))
printf("\n罗马不是一天建成的, 继续保持哦:)\n");
else
printf("\n罗马不是一天毁灭的, 我们来建设吧\n");
return 0;
}
任务四：
#include<stdio.h>
int main()
{
double x, y;
char c1, c2, c3;
int a1, a2, a3;
scanf_s("%d%d%d", &a1, &a2, &a3);
printf("a1 = %d, a2 = %d, a3 = %d\n", a1, a2, a3);
scanf_s("%c%c%c", &c1, &c2, &c3);
printf("c1 = %c, c2 = %c, c3 = %c\n", c1, c2, c3);
scanf_s("%lf,%lf", &x, &y);
printf("x = %f, y = %lf\n", x, y);
return 0;
}
实验五：
#include <stdio.h>
int main()
{
int year;
year = (int)(1e9 / (365.0 * 24 * 3600) + 0.5);
printf("10亿秒约等于%d年\n", year);
return 0;
}
实验六：
#include <stdio.h>
#include <math.h>
int main()
{
double x, ans;
while (scanf_s("%lf", &x) != EOF)
{
ans = pow(x, 365);
printf("%.2f的365次方: %.2f\n", x, ans);
printf("\n");
}
return 0;
}
实验七：
#include <stdio.h>
int main() {
char type;
double temp;
while (1) {
printf("输入温度（例：C 36.5）或q退出：");
if (scanf_s(" %c", &type) != 1 || type == 'q' || type == 'Q') break;
scanf_s("%lf", &temp);
if (type == 'C' || type == 'c')
printf("%.2fC = %.2fF\n", temp, temp * 9 / 5 + 32);
else if (type == 'F' || type == 'f')
printf("%.2fF = %.2fC\n", temp, (temp - 32) * 5 / 9);
while (getchar() != '\n');
}
return 0;
}
实验八：
#include <stdio.h>
#include <math.h>
int main() {
double a, b, c, s, area;
printf("请输入三角形的三条边长（用空格分隔）: ");
scanf_s("%lf %lf %lf", &a, &b, &c);
if (a <= 0 || b <= 0 || c <= 0) {
printf("错误：边长必须为正数！\n");
return 1;
}
if (a + b <= c || a + c <= b || b + c <= a) {
printf("错误：输入的边长无法构成三角形！\n");
return 1;
}
s = (a + b + c) / 2;
area = sqrt(s * (s - a) * (s - b) * (s - c));
printf("三角形面积: %.2f\n", area);
return 0;
}
