https://leetcode.cn/problems/subarray-product-less-than-k/description/
同向双指针,没什么难点
class Solution {int res;public int numSubarrayProductLessThanK(int[] nums, int k) {if(k<=1)return 0;int mSum=1;// i右指针,子数组的右端点for(int i=0,j=0;i<nums.length;i++){mSum*=nums[i];while(mSum >= k) // 当不满足要求时,缩小范围{mSum/=nums[j];j++;}res += i-j+1;}return res;}
}