WPF的Popup自动显示隐藏

简单实现鼠标移过Popup自动显示和隐藏的功能；

在xaml.cs中实现，首先创建一个定时器，设置300ms的延时：

        DispatcherTimer timer;

        public Function1View()
        {
            InitializeComponent();

            timer = new DispatcherTimer();
            timer.Tick += timer_Tick;
            timer.Interval = TimeSpan.FromMilliseconds(300);
        }

z定时器的触发函数中，隐藏Popup：

        void timer_Tick(object sender, EventArgs e)
        {
            menuPopup.IsOpen = false;
        }

Popup和目标控件的鼠标进入和离开函数：

        /// <summary>
        /// 鼠标移走
        /// </summary>
        /// <param name="sender"></param>
        /// <param name="e"></param>
        private void Border_MouseLeave(object sender, MouseEventArgs e)
        {
            timer.Start();
        }
        /// <summary>
        /// 鼠标移走
        /// </summary>
        /// <param name="sender"></param>
        /// <param name="e"></param>
        private void menuPopup_MouseLeave(object sender, MouseEventArgs e)
        {
            timer.Start();
        }
        /// <summary>
        /// 鼠标进入
        /// </summary>
        /// <param name="sender"></param>
        /// <param name="e"></param>
        private void Border_MouseEnter(object sender, MouseEventArgs e)
        {
            menuPopup.IsOpen = true;
            timer.Stop();
        }
        /// <summary>
        /// 鼠标进入
        /// </summary>
        /// <param name="sender"></param>
        /// <param name="e"></param>
        private void menuPopup_MouseEnter(object sender, MouseEventArgs e)
        {
            menuPopup.IsOpen = true;
            timer.Stop();
        }

实现效果：